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NSW Opportunity Class Placement Test · 35 questions · 40 minutes · no calculator
First work out the right side: 19 + 8 = 27. So 54 − the missing number = 27, which means the missing number = 54 − 27 = 27.
Take 700 from 18,403. 18,403 − 700 = 17,703.
3:50 pm to 4:50 pm is 1 hour. 4:50 pm to 6:15 pm is 1 hour 25 minutes. Total = 2 hours 25 minutes.
One-third of 36 is 12, so two-thirds is 2 × 12 = 24.
These are the square numbers: 1×1, 2×2, 3×3, 4×4, 5×5. So the 7th term is 7×7 = 49.
Bananas = 18, oranges = 9. Difference = 18 − 9 = 9.
Books: 3 × $7.50 = $22.50. Pencils: 2 × $1.20 = $2.40. Total = $22.50 + $2.40 = $24.90.
Six 50c = $3.00 and eight 20c = $1.60, together $4.60. What is left is $4.65 − $4.60 = $0.05, which is exactly 1 five-cent coin.
The gaps are 5, 7, 9, 11 (the odd numbers). The next gap is 13, so the next number is 35 + 13 = 48.
Every square is also a rectangle (four right angles, opposite sides equal). The other statements are all false.
1 L = 1,000 mL, so 2.5 × 1,000 = 2,500 mL.
Check each one.
So Statements 2 and 3.
Area = length × width = 6 × 4 = 24 m².
Increase = 24 − 4 = 20 °C.
Treat it as an 8 × 5 = 40 cm² rectangle with a 3 × 2 = 6 cm² corner removed. Area = 40 − 6 = 34 cm².
Q + 5 = 13, so Q = 8. And 5 + R = 17, so R = 12. So 96.
H has two lines of symmetry: one down the middle and one across the middle. E has one, F and Z have none, and M has one.
The 2 east and 2 west cancel out, so she ends up directly below the start. She went 3 north then 5 south, which is 2 south overall. So she is 2 metres away.
From the 1st to the 20th is 19 days. 19 = 2 weeks (14 days) + 5 days. Five days after Tuesday is Sunday (Wed, Thu, Fri, Sat, Sun).
Work backwards from 25: take off 7 to get 18, then halve it to get 9.
Reading, Maths and Sport are each a quarter of the circle, so they are equal. The other statements are all false.
Four equal sides with no right angles is a rhombus. A square also has equal sides but its angles are right angles.
Change = $10.00 − $2.20 = $7.80. Nine 50c coins = $4.50, leaving $3.30. To use the most 20c coins, $3.30 holds at most 16 of them ($3.20), with the last 10c made of two 5c coins. So 16.
Red = of 30 = 10. Blue = of 30 = 6. Green = 30 − 10 − 6 = 14.
In the row of four faces (B, A, C, F), folding makes A the front and F the back, so A is opposite F. D and E fold to the top and bottom, opposite each other.
Bea + (Bea + 4) + (Bea + 2) = 30. That is 3 lots of Bea plus 6 = 30, so 3 lots of Bea = 24 and Bea has 8.
The left pan has 14 kg and the right has 9 kg. Check each method:
So Methods 1 and 2.
Two cubes have 6 + 6 = 12 faces in total. When they share a face, one face on each cube is hidden, so 2 faces are hidden. Visible = 12 − 2 = 10.
Each fold doubles the layers: 1 fold = 2 layers, 2 folds = 4 layers. One hole through 4 layers makes 4 holes.
| Day | Mon | Tue | Wed | Thu | Fri | Sat | Sun |
|---|---|---|---|---|---|---|---|
| Cars sold | 8 | 5 | 9 | 4 | 7 | 12 | 6 |
Check each claim.
So Claim 1 only.
Work backwards. Third = triple the second, minus 3 = 24, so triple the second = 27 and the second = 9. Second = triple the first, minus 3 = 9, so triple the first = 12 and the first = 4.
Largest = 853, smallest = 358. 853 − 358 = 495.
3 choices for the first digit, then 2 for the second, then 1 for the last: 3 × 2 × 1 = 6 (257, 275, 527, 572, 725, 752).
Students playing at least one sport = 18 + 14 − 8 = 24 (the 8 who play both were counted twice). Neither = 30 − 24 = 6.
The lengths you can make are the gaps between marks: 2, 5, 11, 3 (5−2), 9 (11−2) and 6 (11−5). So 2, 3, 5, 6, 9 and 11 are possible. 7 cm cannot be made.
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